Edward Stevenson
The Problemist, 1972
Mate in 2
INTENTION: 1.Qd2? BUT 1...Sd4!
Luis Zaragozá
Correction
Show solution
1.Qd2! (2.Qh6#) 1...Sxd7 2.Qb4# 1...Sxe7,Sxd8 2.Qxd3# 1...Sd5 2.Sc8# 1...Sd4 2.Qb4#
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