Allard Pieter Eerkes
The Problemist, 1952
Mate in 2
INTENTION: 1.Se3? BUT 1...Rc3!
Miguel Uris
Correction
Show solution
1.Se3! (2.Sxb5#) 1..Rcxc5 2.Sc2# 1..Rgxc5 2.Sf5# 1..Bxe3 2.dxe3# 1..Rb4 2.Sc2# 1..d5,d6 2.Se6#
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