B J da Costa Andrade
The Problemist, 1943
Mate in 2
INTENTION 1.Sa5? but 1...Se5!
Miguel Uris
Correction
Show solution
1.Sa5! (2.Sb3,Sb7,d4#) 1...Bf6,Qxg7 2.Sb3# 1...Bxf4 2.Sb7# 1...Qxb8 2.d4# 1...bxa5,b5 2.Qa7# 1...S~ 2.S(x)a6# 1...Qc8,Bc8 2.Sb3,d4# 1...Qd8 2.Sb3,Sb7# 1...Bg2 2.Sb3,Sd7,d4
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